2x^2+3xy+4y=38

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Solution for 2x^2+3xy+4y=38 equation: 


Simplifying
2x2 + 3xy + 4y = 38

Reorder the terms:
3xy + 2x2 + 4y = 38

Solving
3xy + 2x2 + 4y = 38

Solving for variable 'x'.

Reorder the terms:
-38 + 3xy + 2x2 + 4y = 38 + -38

Combine like terms: 38 + -38 = 0
-38 + 3xy + 2x2 + 4y = 0

The solution to this equation could not be determined.

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